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anonymous

  • 5 years ago

How do solve 2^( x+1) =x^2-1algebraically.

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  1. anonymous
    • 5 years ago
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    Recognize that \(x^2 -1\) is a difference of squares. Then factor it and cancel an (x+1) (with the restriction that x does not equal -1.

  2. anonymous
    • 5 years ago
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    No, you can't solve it algebraically (exactly)

  3. anonymous
    • 5 years ago
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    but on the left hand side we have 2^(x + 1)

  4. anonymous
    • 5 years ago
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    so x +1 cant be cancelled out

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