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anonymous

  • 5 years ago

Find f '(x) for the function: (9lnx)/x^4 I've gotten it to (9x^3-9lnx X 4x^3)/x^8, but I'm not sure how to simplify it further than that... help?

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  1. anonymous
    • 5 years ago
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    I know it will be [9(1-???)]/x^5, but I don't know what else goes in the parenthesis.

  2. anonymous
    • 5 years ago
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    Factor out x^3 from the numerator then reduce with denominator

  3. anonymous
    • 5 years ago
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    9(1-4lnx)/x^5

  4. anonymous
    • 5 years ago
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    Thank you! :)

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