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anonymous

  • 5 years ago

if x^2 ∝ y^2 then is x ∝ y ???if not,,plz xplain!

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  1. amistre64
    • 5 years ago
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    a linear equation amounts to the highest degree being a "1": y = x+3 when you start sqaureing things, you start to bend the line.... x^2 and y^2 bend and cross the axises twice. making them conic in nature.

  2. amistre64
    • 5 years ago
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    or so i think....

  3. anonymous
    • 5 years ago
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    i askd smthng else sir!

  4. amistre64
    • 5 years ago
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    im sure you did...... :)

  5. anonymous
    • 5 years ago
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    "If x^2 ∝ y^2 then is x ∝ y?" No, now flutter off.

  6. anonymous
    • 5 years ago
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    Wow. Newton.. How about you take your attitude elsewhere. Just because someone is mistaken doesn't mean you get to be uncivil.

  7. amistre64
    • 5 years ago
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    isnt that a german word??

  8. anonymous
    • 5 years ago
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    When someone makes about 5 threads with the same question, then spams other threads with it also, you think they still deserve respect? Nice.

  9. anonymous
    • 5 years ago
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    I think that there are more civil ways to tell someone that they don't need to repeatedly repost the same thing over and over, just as there are less civil ways I could be explaining this to you. If we don't treat each other with respect things quickly devolve into the kind of "NO U" nonsense you see everywhere else online.

  10. anonymous
    • 5 years ago
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    i m sry guys...m jst 16 nd a bit confused

  11. anonymous
    • 5 years ago
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    I could have explained it several ways, like telling him that an equation in x^2 and y^2 only will have symmetry in both axis, so can, by definition, not be a linear equation. Or another way. .... If he'd asked once. Polpak, you can have your 81 fans, and I'll have my superior Mathematical abilities? Deal?

  12. anonymous
    • 5 years ago
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    sry sir .........sir newton!

  13. anonymous
    • 5 years ago
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    You also have a superior attitude, which is the part I take issue with.

  14. anonymous
    • 5 years ago
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    i'll get it cleared somewhere else by the way....u guyz dont fight plzzzzzzz

  15. anonymous
    • 5 years ago
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    dats why i askd polpak his age?

  16. anonymous
    • 5 years ago
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    thank u 4 ur tym!!!

  17. anonymous
    • 5 years ago
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    i dont know hyperbola!

  18. anonymous
    • 5 years ago
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    so cant get ur terms of usage in xplanation....was a bit complex frm ur syd!!!!

  19. anonymous
    • 5 years ago
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    i m an indian and we give due respect to ol even if they dont give us!!!!

  20. anonymous
    • 5 years ago
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    Sketch the graphs.

  21. anonymous
    • 5 years ago
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    hmmm

  22. anonymous
    • 5 years ago
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    x^2 = y^2, therefore x = ±y , so this graph will consist of 2 lines, not one (x=y in the first quadrant, reflected into all the others, which you could see as 2 lines, x = y and x = -y)

  23. amistre64
    • 5 years ago
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    ..... i think that means I was right lol ;)

  24. anonymous
    • 5 years ago
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    The graphs only start curving into hyperbola if y^2 = mx^2 + k, not if y^2 = mx^2 i.e. y^2 propto x^2

  25. amistre64
    • 5 years ago
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    true....

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