if x^2 ∝ y^2 then is x ∝ y ???if not,,plz xplain!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

if x^2 ∝ y^2 then is x ∝ y ???if not,,plz xplain!

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

a linear equation amounts to the highest degree being a "1": y = x+3 when you start sqaureing things, you start to bend the line.... x^2 and y^2 bend and cross the axises twice. making them conic in nature.
or so i think....
i askd smthng else sir!

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

im sure you did...... :)
"If x^2 ∝ y^2 then is x ∝ y?" No, now flutter off.
Wow. Newton.. How about you take your attitude elsewhere. Just because someone is mistaken doesn't mean you get to be uncivil.
isnt that a german word??
When someone makes about 5 threads with the same question, then spams other threads with it also, you think they still deserve respect? Nice.
I think that there are more civil ways to tell someone that they don't need to repeatedly repost the same thing over and over, just as there are less civil ways I could be explaining this to you. If we don't treat each other with respect things quickly devolve into the kind of "NO U" nonsense you see everywhere else online.
i m sry guys...m jst 16 nd a bit confused
I could have explained it several ways, like telling him that an equation in x^2 and y^2 only will have symmetry in both axis, so can, by definition, not be a linear equation. Or another way. .... If he'd asked once. Polpak, you can have your 81 fans, and I'll have my superior Mathematical abilities? Deal?
sry sir .........sir newton!
You also have a superior attitude, which is the part I take issue with.
i'll get it cleared somewhere else by the way....u guyz dont fight plzzzzzzz
dats why i askd polpak his age?
thank u 4 ur tym!!!
i dont know hyperbola!
so cant get ur terms of usage in xplanation....was a bit complex frm ur syd!!!!
i m an indian and we give due respect to ol even if they dont give us!!!!
Sketch the graphs.
hmmm
x^2 = y^2, therefore x = ±y , so this graph will consist of 2 lines, not one (x=y in the first quadrant, reflected into all the others, which you could see as 2 lines, x = y and x = -y)
..... i think that means I was right lol ;)
The graphs only start curving into hyperbola if y^2 = mx^2 + k, not if y^2 = mx^2 i.e. y^2 propto x^2
true....

Not the answer you are looking for?

Search for more explanations.

Ask your own question