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anonymous
 5 years ago
perimeter of rectangle = 34
length of diagonal = 13
width = x
derive x^2  17x + 60 = 0
find the dimensions of the rectangle
anonymous
 5 years ago
perimeter of rectangle = 34 length of diagonal = 13 width = x derive x^2  17x + 60 = 0 find the dimensions of the rectangle

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the optimal measurements?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dimensions of rectangle are 5 and 12

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get that? :(

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0iwas just about to say 5 and 12.... lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you're both gods to me haha

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the 13 diagonal means that there is only a few setups of legs to match.... it just so happens that a 51213 triangle works

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so why is there a quadratic equation in the problem?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0clutter probably :) maybe its part of the next problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2(a+b)=34\quad,\quad\sqrt{a^2+b^2}=13\] solve this system of equations

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you tend to use the derivative stuff to find the max or min area of the box..... but the 13 and 34 tend to limit you already

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks to both of you, but does the quadratic equation have anything to do with the problem

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0it can.... if you dont know the limitations of the other stuff, that can help you to find a length...maybe

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you again, and nikvist too

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Here is how the \[x ^{2}17x+60\] Came into play. Let x = dimension L The perimeter is 34. 342x = 2y which is the other dimension doubled 2y. Divide that by 2 getting: 17x= width. Now use that to get the diagonal.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The quadratic equation is there because you need to find the value of the width using the quadratic equation.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0\[x ^{2}+(17x)^{2}=13^{2}=169\]

radar
 5 years ago
Best ResponseYou've already chosen the best response.0\[x ^{2}+28934x+x ^{2}=169\] \[2x ^{2}34x+289=169\] \[2x ^{2}34x+120=0\] \[x ^{2}17x+60=0\] Did you follow

radar
 5 years ago
Best ResponseYou've already chosen the best response.0You can factor solve it getting (x5)(x12)=0 x=5 and 12
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