## anonymous 5 years ago 8 over x squared -4 plus 6 over 3x-6 solving quadratic equations :(?

1. amistre64

8 6 ------- + -------- like this? x^2 - 4 3x-6

2. anonymous

yes!

3. anonymous

Does that equal something?

4. anonymous

but i dont know HOW to get the answer :/

5. anonymous

which is 2x +12 ------ x^2-4

6. anonymous

$\frac{8}{x^2-4}+\frac{6}{3x-6}$ $= \frac{8(3x-6) + 6(x^2-4)}{(3x-6)(x^2-4)}$ $= \frac{8(3x-6) + 6(x+2)(x-2)}{(3x-6)(x^2-4)}$ $= \frac{8(3x-6) + 2(x+2)3(x-2)}{(3x-6)(x^2-4)}$ $= \frac{8(3x-6) + 2(x+2)(3x-6)}{(3x-6)(x^2-4)}$ $= \frac{(3x-6)[8 + 2(x+2)]}{(3x-6)(x^2-4)}$ $= \frac{[8 + 2(x+2)]}{x^2-4}\text{ , } x \ne 2$ $= \frac{[8 + 2x+4)]}{x^2-4}\text{ , } x \ne 2$ $= \frac{2x+12}{x^2-4}\text{ , } x \ne 2$

7. anonymous

Actually x cannot be -2 either.