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anonymous
 5 years ago
Consider two straight lines L1 (y = 2x +1) and L2 (y=x).
a) What is the slope of line L1 in respect to line L2?
b) What is the equation of line L1 in respect to line L2?
NOTE. Think that the original xy coordinate system has been
rotated in respect to the origin so that line L2 defines the new
xaxis x´ and y´ is the new yaxis!
anonymous
 5 years ago
Consider two straight lines L1 (y = 2x +1) and L2 (y=x). a) What is the slope of line L1 in respect to line L2? b) What is the equation of line L1 in respect to line L2? NOTE. Think that the original xy coordinate system has been rotated in respect to the origin so that line L2 defines the new xaxis x´ and y´ is the new yaxis!

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I need a smart person to answer this, please, I REALLY need to understand this

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1a smart person eh..... hmmm

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the slope of L1 with respect to L2 suggests to me that it is a relative answer. If L2 were flat, what would the slope of L1 be with it..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1y=x has a slope of 1, which is a tan(45)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, I know this, but where do I go from here?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1y = 2x... has a slope of 2....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i aint determined that yet :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1it is the angle of slope 2  slope1 but you use the "angles" and not the slopes

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1what angle has a tan^1(2)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, so, basically, the slope of L1 in relation to slope L2 will be 1, right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am really bad at this sorry... forgot all the high school stuff

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1tan(63.43) = 2 not really, since we have rotated the axis by a certain degree, we need to determine the degrees involved, then you trig stuff to re dress the problem

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1.... we dont need the angles perse, just their ration....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0isn't there a simple way?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1cos(ab) = cos(a)cos(b)sin(a)sin(b)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1cos(a) = 1/sqrt(2) cos(b) = 1/sqrt(5) sin(a) = 1/sqrt(2) sin(a) = 2/sqrt(5)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1cos(ab)=1/sqrt(2) * 1/sqrt(5)  1/sqrt(2) * 2/sqrt(5)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1might be better to work it in tans :) that way we get a new "slope"....tan = slope by the way

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1tan(ab) = tan(a)tan(b)  if I recall correctly 1+tan(a)tan(b)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1tan(a) = 1/1 tan(b)=2/1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1hold up, make a the bigger one... tan(a) = 2; tan(b)=1 21  = 1/3 right? 1+2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the new slope is 1/3 :) what was the second part?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0equation of the line L1 in relation to eq of the line of L2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1y=(1/3)x + b just gotta determine where the lines intersect and use that as a parameter for the new system....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1they originally intersect at x=1; y=1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the new point of intersection is the length of sqrt(2)....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1so the new coord to fill in is (sqrt(2),0)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.10 = (1/3)(sqrt(2)) + b b= sqrt(2)/3 y = (1/3)x  (sqrt(2)/3) should be it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1why sqrt(2)? the original lines cross at (1,1) when we rotate the axis to accomodate the new axises.... that point is still there, but we use the distance of it from the origin as the x intercept

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.111sqrt(2) is the triangle of a 45 degree..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get so good at maths?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1by messing up alot lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1my son is nagging me for the laptop....ciao :)
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