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anonymous
 5 years ago
how would you get the derivative of xy+2x+3x^2=1 using implicit differentiation
anonymous
 5 years ago
how would you get the derivative of xy+2x+3x^2=1 using implicit differentiation

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you use the chaine rule on every y you see... or more easily add y' to your y derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so...your answer should look like 1(y')+2+6x=1...y'=16x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do product rule for xy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y' + 2 + 6x = 0, so y' = 6x  2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0xy'+y+2+6x=0....xy'=6x2....y'=(6x2)/x, if I'm not mistaken

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0My bad  My answer is wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0MathTy is correct. The chain differential of xy is xy' + y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0teamwork, anyways that should be your answer, doing math on the computer without writting it down can be hard

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thank you everyone for your help
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