how would you get the derivative of xy+2x+3x^2=1 using implicit differentiation

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how would you get the derivative of xy+2x+3x^2=1 using implicit differentiation

Mathematics
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you use the chaine rule on every y you see... or more easily add y' to your y derivative
Use y = 1/x - 2 - 3x
so...your answer should look like 1(y')+2+6x=1...y'=-1-6x

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Other answers:

oops
do product rule for xy
= 0, not 1
y' + 2 + 6x = 0, so y' = -6x - 2
xy'+y+2+6x=0....xy'=-6x-2....y'=(-6x-2)/x, if I'm not mistaken
My bad - My answer is wrong
MathTy is correct. The chain differential of xy is xy' + y
teamwork, anyways that should be your answer, doing math on the computer without writting it down can be hard
ok thank you everyone for your help

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