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anonymous

  • 5 years ago

how would you get the derivative of xy+2x+3x^2=1 using implicit differentiation

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  1. anonymous
    • 5 years ago
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    you use the chaine rule on every y you see... or more easily add y' to your y derivative

  2. anonymous
    • 5 years ago
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    Use y = 1/x - 2 - 3x

  3. anonymous
    • 5 years ago
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    so...your answer should look like 1(y')+2+6x=1...y'=-1-6x

  4. anonymous
    • 5 years ago
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    oops

  5. anonymous
    • 5 years ago
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    do product rule for xy

  6. anonymous
    • 5 years ago
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    = 0, not 1

  7. anonymous
    • 5 years ago
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    y' + 2 + 6x = 0, so y' = -6x - 2

  8. anonymous
    • 5 years ago
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    xy'+y+2+6x=0....xy'=-6x-2....y'=(-6x-2)/x, if I'm not mistaken

  9. anonymous
    • 5 years ago
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    My bad - My answer is wrong

  10. anonymous
    • 5 years ago
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    MathTy is correct. The chain differential of xy is xy' + y

  11. anonymous
    • 5 years ago
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    teamwork, anyways that should be your answer, doing math on the computer without writting it down can be hard

  12. anonymous
    • 5 years ago
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    ok thank you everyone for your help

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spraguer (Moderator)
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