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anonymous
 5 years ago
Given the following differential equation find the solution that passes through (1,1). You may use separation of variables.
dy/dt = t / (y^2 * sqrt(1+t^2))
anonymous
 5 years ago
Given the following differential equation find the solution that passes through (1,1). You may use separation of variables. dy/dt = t / (y^2 * sqrt(1+t^2))

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0[S] y^2 dy =[S] t/sqrt(1+t^2) dt

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(1/3)y^3 = (1/2)(sqrt(1+t^2)) is that right :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i think that ''1/2'' cancels ....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(1/3)y^3 = sqrt(1+t^2) +c 1,1 seems like coordinantes, but are they t=1 and y=1?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(1/3) = sqrt(2) +c c = sqrt(2)/3 (1/3) y^3 = sqrt(1+t^2) + sqrt(2)/3....thats the best i got....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you very much! c = (1/3)  sqrt(2) The final answer is: (3(sqrt(1+t^2)+((1/3)sqrt(2))))^(1/3) = y(t) Thanks!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0youre welcome :) just glad I was right lol
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