## anonymous 5 years ago (1/2x^2)^3(-8x^3)^2

1. anonymous

Okay Zechariah, if I've read correctly, you have this: $\left( \frac{1}{2x^2} \right)^3(-8x^3)^2$You need to use power laws to simplify. If you have$\left( \frac{a}{b} \right)^n$this will be equal to$\frac{a^3}{b^3}$Also, if you have$(ab)^n$this will be equal to$a^nb^n$and if you have$(a^m)^n$this will be equal to $a^{mn}$You can apply these two laws to what you've got. So,$\left( \frac{1}{2x^2} \right)^3=\frac{1}{(2x^2)^3}=\frac{1}{2^3(x^2)^3}=\frac{1}{8x^6}$and $(-8x^3)^2=(-1)^2(8)^2(x^3)^2=64x^6$So your expression becomes$\left( \frac{1}{2x^2} \right)^3(-8x^3)^2=\frac{1}{8x^6} \times 64x^6=\frac{64x^6}{8x^6}=\frac{8 \times 8 x^6}{8x^6}=8$

2. anonymous

Above I said$\left( \frac{a}{b} \right)^n=\frac{a^3}{b^3}$It doesn't; it's a typo. It should read,$\left( \frac{a}{b} \right)^n=\frac{a^n}{b^n}$

3. anonymous

PS: I like your "About Me" statement :) You have the right attitude.

4. anonymous

Thank you