Find the solution of the following differential equation that passes through (-1,-1). You may use separation of variables.
dy/dt = [ 2t(y+1) ] / [y]
This is what I have after separation of variables and integration of both sides:
y - ln(y+1) = t^2 +c
Plugging in (-1,-1) would not work as ln(0) does not exist. Is there another way to solve this problem?
Thanks in advance!

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this is weird my solution also has ln(y+1)

it seems like they would give points for which the function is defined

my solution doesn't.

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