prove that the segment joining the midpoints of the diags. of a trapezoid is parallel to the bases and has a length equal to half the difference of the lengths of the bases.

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prove that the segment joining the midpoints of the diags. of a trapezoid is parallel to the bases and has a length equal to half the difference of the lengths of the bases.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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listen...........join the top left vertice of trapezium with mid point of the diagonal from bottom left to top right.....!!!!!!!got it..... shall i continue fuether?????
i get the parallel thing, i don't get the how the length = half the difference of the bases. i keep getting half the SUM of the bases... and this is coordinate geom. btw like trap. vertices are (a,0), (0,0), (d,c), and (b,c)

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