hi everyone i need help for my assignment

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

hi everyone i need help for my assignment

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

There are a lot of questions, chai.
You can't really answer the first two since you only have one point in each part. You need two points to calculate the distance. I can do the third point:\[d=\sqrt{(3-(-1))^2+(-\sqrt{2}-\sqrt{2})^2}=\sqrt{4^2+(2\sqrt{2})^2}\]\[=\sqrt{16+8}=\sqrt{24}=2\sqrt{6}\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

In general, if you have two points in the x-y plane, such as\[(x_1,y_1)\]and\[(x_2,y_2)\]then the distance between them is\[d=\sqrt{(x_2-x_1)^2+(y_2-y_2)^2}\]You have to apply this formula each time you want to find the distance.
For your triangle question, you draw up a set of axes and plot each of the three points per triangle. You then find the length of each side by using the distance formula, using the two points that are at the end of the line.
Chai, I can't answer your last question either because you don't have a an ordered pair along with the slope. You'd need to have something like (-13,5) with slope m=1; you only have -13 and m=1, etc. Sorry...I take it your teacher didn't actually write anything down for you. It's not your fault.
thanks for helping me, i am done answering my first two problem. im sorry i was mis write the exact actually thats not (31, 74) but (3, 1) (7. 4) and (0, 4)(-3, 0)
You're welcome, Chai. Good luck.
can i ask favor to you if its okay? please answer my third question in my first problem please. i dont know how to solve that because of the squaroot. if its okay
I think I did...look above^^
im sorry, i did not notice. ahmm, Hero can you answer about slope problem. problem is (-1, 3) m= 1 and (4, 0) m= 2/3
All you have to do is plot your point, and then using the definition of the slope (i.e. rise over run) work out another point and plot it. You'll have two points and you can then draw your line. First point: start at (-1,3) and since m=1=1/1, for every 1 unit you move across, move up one unit. So you'd have another point at (0,4). Draw a line between these two points. For the second: start at (4,0) and since m=2/3, for every 3 points you move across to the right, move up two points. Your next point would then be at (7,2). Plot this and draw a line between the two points.
I'm signing out for the rest of the day. If you need anymore help quickly, post your question in the "Ask a question" box. Good luck.
thankyou hero, hero im finish drwing a triangle of my second problem but i dont know how to solve this using the formula of distance to find the length since they are three. the problem are: a, (2 -1) (4, 2) (5, 0) b, (0 -3) (3,0) (0 -4). can youu help me again to solve?
Chai, you're going to have to find three distances for each triangle. To find each distance, you need to use the two points that are on either end of the side of the triangle you're looking at. For example, in the triangle I've attached, side 'a' will have the points (2,-1), (4,2) To find the distance, you have\[a=\sqrt{(4-2)^2+(2-(-1))^2}=\sqrt{2^2+3^2}=\sqrt{13}\]You need to repeat the process for the other two sides. If you have difficulty, post the question to someone who will be around now. Post this link http://openstudy.com/updates/4da16b9dd6938b0beb509e4d?source=email#/updates/4da16b9dd6938b0beb509e4d and they should be able to get to this post. Good luck.
1 Attachment
thankyou for the help hero. now im done doing my assignment. thankyou so much
You're welcome Chai. Become a fan ;D

Not the answer you are looking for?

Search for more explanations.

Ask your own question