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yes

how do i solve it?

so if I had f(x)=\[\sqrt{6-3x}\] i would add 6 to both sides

I get so confused when it is a negative I am writing it down step by step

I got it no negative number

I got it that is what i got to
if i have a problem \[\sqrt{x-1} divided by 1\]

this here is a fraction with a "1" in its bottom part, a 1 in the denominator correct?

1 is the numerator

sqrt(x-1)
-------- is what you have written; is this wrong?
1

yes the one is on top

I got [1,inf)

is there a divided by sign between the square root and that "1" ?
sqrt(x-1) [divide sign] 1 ???

[1,inf) is correct :)

\[1 \over \sqrt{x-1?}\]

okay why

so it is (-inf,inf)

on another problem they have 1 over\[\sqrt{2x+2}\] and came up with -1/2,inf

is that because it was 2x+1

1
---------- correct?
sqrt(2x + 2)

never mind I needed to read on

Thank you you have been a lot of help very smart person

thanx :) and youre welcome

I think I can pass this part of my finals

yay!!!