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anonymous
 5 years ago
Integrate f(x) = 4x^3 + 3 on the interval [0, 2].
anonymous
 5 years ago
Integrate f(x) = 4x^3 + 3 on the interval [0, 2].

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we can split this integral up as well, and that "0" part is pointless later on ;) [S] 4x^3 dx + [S] 3 dx x^4 + 3x  [0,2] [ (2)^4 + 3(2) ]  [ (0)^4 + 3(0)] = ?? see I told you the zero was pointless

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Got it! =D, but it's 22.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol ..... so I cant add :)
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