anonymous
  • anonymous
Use the graph to determine each limit.
Mathematics
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chestercat
  • chestercat
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anonymous
  • anonymous
i) \[\lim_{x \rightarrow 2^{-}} f(x)\] ii) \[\lim_{x \rightarrow 2^{+}} f(x)\] iii) \[\lim_{x \rightarrow 2} f(x)\] iv) \[\lim_{x \rightarrow 2^{-}} f(x)\] v) \[\lim_{x \rightarrow 0^{+}} f(x)\] vi) \[\lim_{x \rightarrow 0} f(x)\]
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anonymous
  • anonymous
ERRATA: iv) \[\lim_{x \rightarrow 0^{-}} f(x)\]
amistre64
  • amistre64
lets call the left graph "f(x)" and the right graph "g(x)" that way we can tell what were talking about.... now are we supposed to take the specified limit as it pertains to both graphs individually?

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anonymous
  • anonymous
we must answer all for each graph.
amistre64
  • amistre64
so the limits are 2 from the right, 2 from the left, 0 from the right, 0 from the left, and at 0 and at 2..if I read this correctly
anonymous
  • anonymous
Yes, that's correct.
amistre64
  • amistre64
a = f(x) lim{2+} = +infinity; lim{2-} = -infinity; lim{2} = not exist.
amistre64
  • amistre64
a = f(x) lim{0+} = 0; lim{0+} is undefined, no graph there; lim{0} = 0 maybe...but hard to tell since the 0- is gone....
anonymous
  • anonymous
you mean, lim{0-} is undefined, right?
amistre64
  • amistre64
umm.... yeah, thats what I meant :)
anonymous
  • anonymous
ohh! thanks! I do not know how to define it. let's b.
amistre64
  • amistre64
b=g(x) lim{2+} = -1; lim{2+} =-1 ; lim{2} = -1 lim{0+}=1; lim{0-}=undefined; lim{0}=1 I would assume since it is a solid "dot"
amistre64
  • amistre64
did it again didnt i....lim{2-} = -1
anonymous
  • anonymous
haha. np. btw, thanks!
amistre64
  • amistre64
youre welcome :)

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