describe the vertical asymptotes and holes for the graph of y=(x-2)/[(x+2)(x-2)]

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describe the vertical asymptotes and holes for the graph of y=(x-2)/[(x+2)(x-2)]

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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there is a hole at x=2 and x=-2 there is a vertical asymp.
now what do i do to figure that out?
Is it \[\frac{x-2}{(x+2)(x-2)} = \frac{1}{x+2} ?\]

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Other answers:

notice the x-2 cancel x-2=0 implies x cannot 2 since x+2 did not cancel x+2=0 means x=-2 is a veritcal asymp.
oh ok and how is it a vertical asymp.
plug in numbers close to 2 on the left and numbers close 2 on the right to see why
oops -2
as those numbers get close to -2 the bottom is getting closer to 0 which means it is approaching either negative infinity or positive infinity

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