anonymous
  • anonymous
describe the vertical asymptotes and holes for the graph of y=(x-2)/[(x+2)(x-2)]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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myininaya
  • myininaya
there is a hole at x=2 and x=-2 there is a vertical asymp.
anonymous
  • anonymous
now what do i do to figure that out?
anonymous
  • anonymous
Is it \[\frac{x-2}{(x+2)(x-2)} = \frac{1}{x+2} ?\]

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myininaya
  • myininaya
notice the x-2 cancel x-2=0 implies x cannot 2 since x+2 did not cancel x+2=0 means x=-2 is a veritcal asymp.
anonymous
  • anonymous
oh ok and how is it a vertical asymp.
myininaya
  • myininaya
plug in numbers close to 2 on the left and numbers close 2 on the right to see why
myininaya
  • myininaya
oops -2
myininaya
  • myininaya
as those numbers get close to -2 the bottom is getting closer to 0 which means it is approaching either negative infinity or positive infinity

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