anonymous
  • anonymous
simplify the expression x^6y^3/x^3y
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
x^(3y*(y^2 -1) is it just a part of the task?
anonymous
  • anonymous
\[x ^{6y ^{3}}/x ^{3y}\] ?
anonymous
  • anonymous
or \[x ^{(6y)^{3}}/x ^{3y}\]

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anonymous
  • anonymous
hmm good question - forgot the other possibility :P
anonymous
  • anonymous
the 1st one
anonymous
  • anonymous
mine should be right :P
anonymous
  • anonymous
its not your sorry=) but its peddani the 1st one
anonymous
  • anonymous
i know that you answered to peddani - my first answer should be the simplification of the first one of peddani just add a bracket in the end
anonymous
  • anonymous
i dont get it
anonymous
  • anonymous
x^2/x^3 = x^(2-3) so is x^6y^3/x^3y equal to: x^[(6y^3)-3y] then you can factorise 3y: x^[3y (2y^2 - 1)] but what do you need a simplification for?

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