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anonymous

  • 5 years ago

simplify the expression x^6y^3/x^3y

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  1. anonymous
    • 5 years ago
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    x^(3y*(y^2 -1) is it just a part of the task?

  2. anonymous
    • 5 years ago
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    \[x ^{6y ^{3}}/x ^{3y}\] ?

  3. anonymous
    • 5 years ago
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    or \[x ^{(6y)^{3}}/x ^{3y}\]

  4. anonymous
    • 5 years ago
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    hmm good question - forgot the other possibility :P

  5. anonymous
    • 5 years ago
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    the 1st one

  6. anonymous
    • 5 years ago
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    mine should be right :P

  7. anonymous
    • 5 years ago
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    its not your sorry=) but its peddani the 1st one

  8. anonymous
    • 5 years ago
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    i know that you answered to peddani - my first answer should be the simplification of the first one of peddani just add a bracket in the end

  9. anonymous
    • 5 years ago
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    i dont get it

  10. anonymous
    • 5 years ago
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    x^2/x^3 = x^(2-3) so is x^6y^3/x^3y equal to: x^[(6y^3)-3y] then you can factorise 3y: x^[3y (2y^2 - 1)] but what do you need a simplification for?

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spraguer (Moderator)
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