anonymous
  • anonymous
Let a ≠ 0, b and c be real numbers. Show that, if there is areal valued f such that f(f(x)) = ax^2 + bx + c for every real x, then (b - 1)^2 ≤ 4(ac + 1) I don't know how to this, but I was told that several guys with a good knowledge in calculus had a lot of trouble and a smart 14- year-old boy gave a correct proof using high school algebra. Can someone help?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Source?
anonymous
  • anonymous
What do you mean source?
anonymous
  • anonymous
Where is it from?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I saw this question posted on a different platform and nobody solved it. So I was wondering if someone here could.
anonymous
  • anonymous
Where?
anonymous
  • anonymous
This site is hardly full of olympiad-level people FWIW
anonymous
  • anonymous
answers.yahoo.com
anonymous
  • anonymous
Oh lol, probably isn't too hard though then, I thought you meant somewhere like AoPS ¬_¬. Still not my style, though.
anonymous
  • anonymous
What's a AoPS?

Looking for something else?

Not the answer you are looking for? Search for more explanations.