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anonymous

  • 5 years ago

consider f(x) = X^2+1 fill in the following table and approximate the instananeous rate of chnage of f as x approahces 2 from the left. lets use the number 1

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  1. amistre64
    • 5 years ago
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    dy/dx = 2x..... so at x=1, the rate of change is 2

  2. anonymous
    • 5 years ago
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    Not sure exactly what it means by use the number 1?

  3. amistre64
    • 5 years ago
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    er....-2 ;)

  4. anonymous
    • 5 years ago
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    Ok I agree with amistre

  5. amistre64
    • 5 years ago
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    nahnahnah.....i got me peepers on backwards

  6. anonymous
    • 5 years ago
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    h=1

  7. amistre64
    • 5 years ago
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    2....my vote is 2 lol

  8. anonymous
    • 5 years ago
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    Ok so basically the question wants the derivative at 2. So what amistre did was calculate the derivative of the function and then plugged 1 in for x, which equals 2.

  9. anonymous
    • 5 years ago
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    i may have forgotten to leave some info. he says 2, 2+5 should be used to solve the problem

  10. anonymous
    • 5 years ago
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    2,2+h i mean

  11. amistre64
    • 5 years ago
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    2+5? what...are we generating random functions now :)

  12. anonymous
    • 5 years ago
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    2,2+h i mean

  13. amistre64
    • 5 years ago
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    you want to know the "limit" definition of the function as it approaches 2.... right?

  14. anonymous
    • 5 years ago
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    Ah that explains it

  15. anonymous
    • 5 years ago
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    yes this looks like a limit question

  16. amistre64
    • 5 years ago
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    f(2+h) - f(2) ---------- something like that/ h

  17. amistre64
    • 5 years ago
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    (2+h)^2+1 - (2^2+1) ------------------- h

  18. amistre64
    • 5 years ago
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    4 +8h + h^2 -4 -1 ---------------- h

  19. anonymous
    • 5 years ago
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    yes, he skips some steps but here is what he has f(2+h)-f(2) --------- h f(2+1)-f(2) ------- 1

  20. amistre64
    • 5 years ago
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    make that 4h up there....

  21. amistre64
    • 5 years ago
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    4h + h^2 -1 -------------- h

  22. amistre64
    • 5 years ago
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    al also dropped a "1" on the floor, but youlll find it :) h(4+h) ------ h 4+h -------- h

  23. amistre64
    • 5 years ago
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    make h a 1?..that sounds odd..better relook at that

  24. anonymous
    • 5 years ago
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    there are 3 different h's 1, .1 and .01 and for this answer, the answer is five. after i do the others it is approaching 4

  25. amistre64
    • 5 years ago
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    9 +1 - 4 - 1 ---------- = 5 alrighty 1

  26. amistre64
    • 5 years ago
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    so you want x^2 + 1 at x = 2.... y' = 2x; 2(2) = 4

  27. amistre64
    • 5 years ago
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    what your doing now is learning the "long" version that gives credence to the derivative..

  28. anonymous
    • 5 years ago
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    i think so. do you want me to put the problem in here exactly how i am looking at it?

  29. amistre64
    • 5 years ago
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    nah, just filll out your tables and get your answer as 4 ;)

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