consider f(x) = X^2+1 fill in the following table and approximate the instananeous rate of chnage of f as x approahces 2 from the left. lets use the number 1

- anonymous

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- amistre64

dy/dx = 2x..... so at x=1, the rate of change is 2

- anonymous

Not sure exactly what it means by use the number 1?

- amistre64

er....-2 ;)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

Ok I agree with amistre

- amistre64

nahnahnah.....i got me peepers on backwards

- anonymous

h=1

- amistre64

2....my vote is 2 lol

- anonymous

Ok so basically the question wants the derivative at 2. So what amistre did was calculate the derivative of the function and then plugged 1 in for x, which equals 2.

- anonymous

i may have forgotten to leave some info. he says 2, 2+5 should be used to solve the problem

- anonymous

2,2+h i mean

- amistre64

2+5? what...are we generating random functions now :)

- anonymous

2,2+h i mean

- amistre64

you want to know the "limit" definition of the function as it approaches 2.... right?

- anonymous

Ah that explains it

- anonymous

yes this looks like a limit question

- amistre64

f(2+h) - f(2)
---------- something like that/
h

- amistre64

(2+h)^2+1 - (2^2+1)
-------------------
h

- amistre64

4 +8h + h^2 -4 -1
----------------
h

- anonymous

yes,
he skips some steps but here is what he has
f(2+h)-f(2)
---------
h
f(2+1)-f(2)
-------
1

- amistre64

make that 4h up there....

- amistre64

4h + h^2 -1
--------------
h

- amistre64

al also dropped a "1" on the floor, but youlll find it :)
h(4+h)
------
h
4+h
--------
h

- amistre64

make h a 1?..that sounds odd..better relook at that

- anonymous

there are 3 different h's
1, .1 and .01 and for this answer, the answer is five. after i do the others it is approaching 4

- amistre64

9 +1 - 4 - 1
---------- = 5 alrighty
1

- amistre64

so you want x^2 + 1 at x = 2....
y' = 2x; 2(2) = 4

- amistre64

what your doing now is learning the "long" version that gives credence to the derivative..

- anonymous

i think so. do you want me to put the problem in here exactly how i am looking at it?

- amistre64

nah, just filll out your tables and get your answer as 4 ;)

Looking for something else?

Not the answer you are looking for? Search for more explanations.