A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
consider f(x) = X^2+1 fill in the following table and approximate the instananeous rate of chnage of f as x approahces 2 from the left. lets use the number 1
anonymous
 5 years ago
consider f(x) = X^2+1 fill in the following table and approximate the instananeous rate of chnage of f as x approahces 2 from the left. lets use the number 1

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0dy/dx = 2x..... so at x=1, the rate of change is 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not sure exactly what it means by use the number 1?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok I agree with amistre

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0nahnahnah.....i got me peepers on backwards

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02....my vote is 2 lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok so basically the question wants the derivative at 2. So what amistre did was calculate the derivative of the function and then plugged 1 in for x, which equals 2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i may have forgotten to leave some info. he says 2, 2+5 should be used to solve the problem

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02+5? what...are we generating random functions now :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you want to know the "limit" definition of the function as it approaches 2.... right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes this looks like a limit question

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0f(2+h)  f(2)  something like that/ h

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(2+h)^2+1  (2^2+1)  h

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.04 +8h + h^2 4 1  h

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, he skips some steps but here is what he has f(2+h)f(2)  h f(2+1)f(2)  1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0make that 4h up there....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.04h + h^2 1  h

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0al also dropped a "1" on the floor, but youlll find it :) h(4+h)  h 4+h  h

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0make h a 1?..that sounds odd..better relook at that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there are 3 different h's 1, .1 and .01 and for this answer, the answer is five. after i do the others it is approaching 4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.09 +1  4  1  = 5 alrighty 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so you want x^2 + 1 at x = 2.... y' = 2x; 2(2) = 4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0what your doing now is learning the "long" version that gives credence to the derivative..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think so. do you want me to put the problem in here exactly how i am looking at it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0nah, just filll out your tables and get your answer as 4 ;)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.