anonymous
  • anonymous
consider f(x) = X^2+1 fill in the following table and approximate the instananeous rate of chnage of f as x approahces 2 from the left. lets use the number 1
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

amistre64
  • amistre64
dy/dx = 2x..... so at x=1, the rate of change is 2
anonymous
  • anonymous
Not sure exactly what it means by use the number 1?
amistre64
  • amistre64
er....-2 ;)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Ok I agree with amistre
amistre64
  • amistre64
nahnahnah.....i got me peepers on backwards
anonymous
  • anonymous
h=1
amistre64
  • amistre64
2....my vote is 2 lol
anonymous
  • anonymous
Ok so basically the question wants the derivative at 2. So what amistre did was calculate the derivative of the function and then plugged 1 in for x, which equals 2.
anonymous
  • anonymous
i may have forgotten to leave some info. he says 2, 2+5 should be used to solve the problem
anonymous
  • anonymous
2,2+h i mean
amistre64
  • amistre64
2+5? what...are we generating random functions now :)
anonymous
  • anonymous
2,2+h i mean
amistre64
  • amistre64
you want to know the "limit" definition of the function as it approaches 2.... right?
anonymous
  • anonymous
Ah that explains it
anonymous
  • anonymous
yes this looks like a limit question
amistre64
  • amistre64
f(2+h) - f(2) ---------- something like that/ h
amistre64
  • amistre64
(2+h)^2+1 - (2^2+1) ------------------- h
amistre64
  • amistre64
4 +8h + h^2 -4 -1 ---------------- h
anonymous
  • anonymous
yes, he skips some steps but here is what he has f(2+h)-f(2) --------- h f(2+1)-f(2) ------- 1
amistre64
  • amistre64
make that 4h up there....
amistre64
  • amistre64
4h + h^2 -1 -------------- h
amistre64
  • amistre64
al also dropped a "1" on the floor, but youlll find it :) h(4+h) ------ h 4+h -------- h
amistre64
  • amistre64
make h a 1?..that sounds odd..better relook at that
anonymous
  • anonymous
there are 3 different h's 1, .1 and .01 and for this answer, the answer is five. after i do the others it is approaching 4
amistre64
  • amistre64
9 +1 - 4 - 1 ---------- = 5 alrighty 1
amistre64
  • amistre64
so you want x^2 + 1 at x = 2.... y' = 2x; 2(2) = 4
amistre64
  • amistre64
what your doing now is learning the "long" version that gives credence to the derivative..
anonymous
  • anonymous
i think so. do you want me to put the problem in here exactly how i am looking at it?
amistre64
  • amistre64
nah, just filll out your tables and get your answer as 4 ;)

Looking for something else?

Not the answer you are looking for? Search for more explanations.