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anonymous
 5 years ago
consider f(x)=x^2+1
find f'(1) using the definition of derivative
anonymous
 5 years ago
consider f(x)=x^2+1 find f'(1) using the definition of derivative

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The definition of a derivative is f(x+h)f(x) all over h.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the "definition" being: f(x+h)  f(x) lim  h right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And yes there is a limit, forgot that part. lim as h approaches 0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes that is right. is get confused when i see h^2 as part of the solution. is the x+h always squared?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What do you mean always squared?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(1+h)^2 + 1  (1^2 + 1)//h h^2 +2h +1 +1 1 1//h h^2 +2h // h h(h+2)//h h+2 is what I get if I did it right....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean party of his answr is 2+2h+h^22/h 2h+h^2/5 h(2+h)/5 2+5=2 yes the limit is zero

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0as h>0; h+2 = 2 f'(x) = 2x; f'(1) = 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the squared question is asked is ist the (1h)^2. will i always sqaure the X+h?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean h. i always seem to hit 5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You will only square the x+h if your function has a 2nd degree in it somewhere.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ok.... f(x) = x^2 +1 whatever value x is ... is the value you use for x. :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0f(1+h) is the value you use and f(1) is the other...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so if its not to a power, you will not square it. just multiply normally?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0....youve confused me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What you are basically doing is plugging in (x+h) into the function for x then subtracting the function itself and dividing by h. All while calculating the limit.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and x = 1 in this instance :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes to see if i understand if it was just +1, not x^2 +, would you not square it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0f(1+h)  f(1) // h [(1+h)^2 +1]  [1^2 +1] // h

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So if you have f(x)=x+1 there is no squaring involved.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is something i always wanted to know thank you. i will be posting a couple more questions of confusion

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0[h^2 +2h +1 +1]  [2] //h h^2 + 2h +2  2 //h h^2 + 2h // h h(h+2)//h lim{h>0} h+2 = 0+2 = 2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0f'(x) = 2x f'(1) = 2(1) = 2 same answers :)
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