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anonymous
 5 years ago
Q:f={(0,5),(1,4),(2,7),(3,14)} and g(x)=3f(x+1)+7
a)evalute g(1)
b) evalute g (1)
c) evalute g(3)
anonymous
 5 years ago
Q:f={(0,5),(1,4),(2,7),(3,14)} and g(x)=3f(x+1)+7 a)evalute g(1) b) evalute g (1) c) evalute g(3)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a)22 b)28 c)is notdefined

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i noe but how did u solve it can u show me tht

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a) g(1)=3f(1+1)+7=3f(0)+7 from the definition of f we see that f(0)=5 so g(1)=3f(0)+7=3(5)+7=22

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0g(x) = 3f(1 + 1) + 7 g(x) = 3f(0) + 7 find f(0) from the Q:F (0,5) g(x) = 3*5 + 7 g(x) = 15 + 7 g(x) = 22 g(x) = 3f(1 + 1) + 7 g(x) = 3f(2) + 7 find f(2) = (2,7) g(x) = 3*7 + 7 g(x) = 21 + 7 g(x) = 28 g(x) = 3f(3 + 1) + 7 g(x) = 3f(4) + 7 find f(4) = not listed don't know what to do

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f is explicitly defined as the given set of ordered pairs, therefore there is nothing to "do" in part (c) , it is simply not defined
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