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anonymous
 5 years ago
. Calculate the slope of the tangent line to the curve at the point where t = 2:
y = e 2t + 1 and x = e t .
anonymous
 5 years ago
. Calculate the slope of the tangent line to the curve at the point where t = 2: y = e 2t + 1 and x = e t .

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ye^(2t) + 1 and x = e^t

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Take the derivative of your function and plug in t = 2. The answer is your slope.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so would it be 2e^2t +1 as my derivative for y which is 110.2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Derivative of a constant is 0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it would be 2et^(2t1).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the 2t is pulled out in front and you must subtract 1 from your exponent.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No 1 in the exponent.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well its y= e^(2t) + 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0umm.... I would take a gander and say: 2 e^(2t)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so once i find the derivative for y i just plug in 2 and thats the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i was confused about what i would need to do with the x=e^t part

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0derivative of e^t is e^t dt

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in this case you can ignore dt since it will be 1.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so i just plug in 2 for that and it would be e^2 so do i i have e^2 divided by my answer for y'(2)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for the final answer?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your answer would just be e^2 I think. What that is saying is the derivative at the point t=2 would be e^2, since the derivative is e^t. not 100% sure on that tho now i'm confusing myself I think.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you want to check your derivative use wolframalpha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean i know the derivatives are right i just dont understand what i do for the problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok. Yes all you do is plug in the value given for t.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok but for both equations or just the y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean i know the derivatives are right i just dont understand what i do for the problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean i know the derivatives are right i just dont understand what i do for the problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats the part i dont get

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok so your saying your not sure since the equation is in terms of X

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0is this a f(x,y) type thing?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It should work the same way I do believe.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01. Eliminate the parameter to find the Cartesian equation for the curve: y = (e ^2t) + 1 and x = e^ t . 2. Calculate the slope of the tangent line to the curve at the point where t = 2: y = (e ^2t) + 1 and x = e ^t .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0those are the two problems we have were doing stuff with polar coordinates and all that so i'm not sure

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm confused on both i just don't get what they want for the answer i guess

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well the first one is simple. The derivative of a function is a function that is used to calculate the slope of it's antiderivative at that point. So lets say the slope of a function at point x = 1 is 2. The derivative's Y value at 1 would be 2, since the derivative allows you to calculate the slope at a given point.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The derivatives Yvalue at x = 1 that is.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so for the first one since x= e^t would the answer be y=x^2 +1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No your derivative will be in terms of X, not Y. So it will be x = your derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The derivative is simply e^t

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i dont know what they want me to do?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0bc it needs to be in cartesian form not polar

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok. you take that derivative (x = e^t) and plug in t=2. You get x = e^2. Your slope at t = 2 is e^2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ah ok well you've gone above my head. We're just about to cover that stuff.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0pjschlotter can you help?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes he can he's very smart :) lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i guess i'll just repost it to see if someone else can help me thanks tho

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i guess i'll just repost it to see if someone else can help me thanks tho
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