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anonymous
 5 years ago
1. Eliminate the parameter to find the Cartesian equation for the curve:
y = e^(2t) + 1 and x = e ^t .
anonymous
 5 years ago
1. Eliminate the parameter to find the Cartesian equation for the curve: y = e^(2t) + 1 and x = e ^t .

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so how do we combine parameter equations into a single equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0would it be y = x^(2) + 1 bc (e^t)^2 = e^2t

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0dunno, depends on if y is a function of x :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y is a function of "t"; so I would assume its independant of "x"

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Wikipedia: "Converting a set of parametric equations to a single equation involves eliminating the variable t from the simultaneous equations . If one of these equations can be solved for t, the expression obtained can be substituted into the other equation to obtain an equation involving x and y only. If x(t) and y(t) are rational functions then the techniques of the theory of equations such as resultants can be used to eliminate t. In some cases there is no single equation in closed form that is equivalent to the parametric equations."

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0solve for "t" and substitute it into the other equation.... is what I think it says :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x = e^t ln(x) = t y = e^(2ln(x)) +1 is what I make of it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that can be simplified probably :) y = e^(2ln(x)) +1 y = e^(ln(x^2)) +1 y = x^2+1 does that make sense?
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