anonymous
  • anonymous
find the product of (5+3i)(5-3i).... would this be 10? I think the 3i's cancel out..but i'm not sure?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
waiit.i just realized this is one where I foil..was thinking it was something else..
anonymous
  • anonymous
so I actually might need help after all. I have (25)+(-15i)+(15i)+(-9i (squared)) Now what do I do with the squared -9i when I rewrite this problem?
radar
  • radar
I think you may be dealing with the imaginary operator i. i is the sq root of -1\[\sqrt{-1}=i\]

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radar
  • radar
So in your answer 25-(-9)=34
radar
  • radar
The product of +3i times -3i is :\[-9i ^{2}=(-9\times-1)=9\]

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