anonymous
  • anonymous
find the product for (5+3i)(5-3i)... I got 24-9a. Does anyone know if this is correct?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Should be 25-9i. You use foil if you've ever been taught that.
anonymous
  • anonymous
No i, my bad.
anonymous
  • anonymous
yeah, that's what I used.. and since the 9i was squared i added a -1. must have calculated it our wrong. Thanks

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anonymous
  • anonymous
yeah, do the i's cancel out? So it would be 25-9?
anonymous
  • anonymous
And actually should be adding. Let's start over lol.
anonymous
  • anonymous
ha good call!
anonymous
  • anonymous
25-9i^2. That is what you should get, which can be simplified.
anonymous
  • anonymous
ok so I can add the 2 and the 25?
anonymous
  • anonymous
Ok. So i represents an imaginary number, it's what you get when you take the square root of a negative number. And the ^ is raised to a power. So we have 25-9i^2. So if \[i=\sqrt{-1}\] then \[i^2=-1\] So we get 25-9(-1)
anonymous
  • anonymous
someone help me
anonymous
  • anonymous
ok so would that be the answer? or can I simplify from there? Since there aren't any i's do I need to add those all to get one number?
anonymous
  • anonymous
Yes to more simplifying. 25-9(-1) is the same as 25+9=34
anonymous
  • anonymous
oh so the answer should be just 34?
anonymous
  • anonymous
Yep.
anonymous
  • anonymous
Thanksabunch
anonymous
  • anonymous
No problem. :)

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