Find the exact positive value of c if the area between the graph of y=x^2-c^2 and the x -axis is 36. Does that mean x=36? but then how do i solve for c?

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Find the exact positive value of c if the area between the graph of y=x^2-c^2 and the x -axis is 36. Does that mean x=36? but then how do i solve for c?

Mathematics
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the area under the curve is equal to 36
c is a constant here that you are trying to determine
in other words; what is the integral of y = x^2 + C such that it equals 36

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Other answers:

youd need to find the solution for: 108 = x (x+sqrt(3C)) (x-sqrt(3C))
or simply put..... since C = c^2 108 = x (x - csqrt(3))(x + csqrt(c))
if you can read thru the typos... i hope its helpful
something like this
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i came out with the answer of 3 by\[\int\limits_{c}^{-c}x^2-c^2\]
taking the antiderivative and getting x^3/3-c^2x
make sure you integrate half of that area then multiply it by 2 to check yourself
then substituting c for x
why would you have to take half
do we want the interval and the value of "c" in the equation to be the same?
because the graph of y = x^2 -C is centered on the y axis; and if you take the area of that, you get "zero' regardless of where you put it :)
both sides cancel each other out.... just a hazard of the trade really
oh I got it Thanks for the help!
youre welcome

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