anonymous
  • anonymous
I have a problem that I am stumped on. Solve for x. Sin(x)=Sin*2(x)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Ok. 0 squared is zero and 1 squared is 1. So where the sine function is 0 and 1 would satisfy the equation. Where is sine 0 and where is sine 1?
anonymous
  • anonymous
0pi+2kpi, pi/2+2kp i
anonymous
  • anonymous
Basically what I'm saying is that the sine function allows you to get 0 and 1 because the sine function varies from -1 to 1. Since you have to have the function itself equal it's square, you have to obtain 0 and 1 to solve your equation.

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anonymous
  • anonymous
What about \[\pi\] and (3/2)\[\pi\]?
anonymous
  • anonymous
Haha nevermind, misread the question. My bad.
anonymous
  • anonymous
pi would work though for sinx=0
anonymous
  • anonymous
Yes, but (3/2)pi would not. That would give you a negative 1, which doesn't satisfy the equation.
anonymous
  • anonymous
sine of pi is 1. so yes it would work. but 3pi/2 would not since it gives you negative 1 for sin(x), where as sin(3pi/2) squared would be 1 since -1 squared is 1
anonymous
  • anonymous
Yes, I got that.
anonymous
  • anonymous
ok. So your answers were correct I believe.
anonymous
  • anonymous
His answers are close, they need to be adjusted.
anonymous
  • anonymous
so my final answer would be 0pi+2kpi, pi+2kpi, and (pi/2)+2kpi?
anonymous
  • anonymous
That's right, but the first two can be combined to one. The last one is correct.
anonymous
  • anonymous
just 0pi+kpi?
anonymous
  • anonymous
Yes. :) Technically you don't need the 0pi, but it doesn't hurt.
anonymous
  • anonymous
Thank you very much. You both have been a big help!
anonymous
  • anonymous
No problem.

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