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anonymous
 5 years ago
How would you write down an integral for the volume of the section of a solid sphere x^2+y^2+z^z<=2 that lies in the first octant and above the plane z=1 in cylindrical coordinates? I know that x=rcosTHETA, y=rsinTHETA and z=z and how to set up a general integral, but not a bounded one...
anonymous
 5 years ago
How would you write down an integral for the volume of the section of a solid sphere x^2+y^2+z^z<=2 that lies in the first octant and above the plane z=1 in cylindrical coordinates? I know that x=rcosTHETA, y=rsinTHETA and z=z and how to set up a general integral, but not a bounded one...

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I also know that dV=rdzdrdTHETA

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So far I have z bounded as 0(lowerbound) and sqrt(2r^2)(upperbound), THETA 0(lowerbound) and .5pi(upperbound) and r as 1(lowerbound) and sqrt(2)(upperbound) Please help! I'm really trying to solve this and not wait for an answer!
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