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anonymous
 5 years ago
use implicit differentiation to find dy/dx:
xe^yye^x=1
anonymous
 5 years ago
use implicit differentiation to find dy/dx: xe^yye^x=1

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Dx(x e^y) = Dx(y e^x) = Dx(1)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x e^y y' + e^y  (y' e^x + e^x) = 0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0aww shucks....ill fan you just so you can be cool like me :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x e^y y' + e^y  y' e^x  e^x = 0 if it aint got a y'...move it to the otherside

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y' (x e^y)  y'(e^x) = e^x  e^y

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0factor out you y' and divide the rest...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y' [(x e^y)  (e^x)] = e^x  e^y y' = e^x  e^y  x e^y  e^x
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