anonymous
  • anonymous
What is the reverse Laplace Transform of X(s)= (s^2 +6)/[(s)(s+1)(s+3)]?
Mathematics
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anonymous
  • anonymous
What is the reverse Laplace Transform of X(s)= (s^2 +6)/[(s)(s+1)(s+3)]?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Partial Fractions it first. Break the denominator up into three parts
anonymous
  • anonymous
\[\frac{s^2 + 6}{(s)(s+1)(s+3)} = \frac{A}{s} + \frac{B}{s+1} \frac{C}{s+3}\]
anonymous
  • anonymous
+ between** B/s+1 + C/s+3 Solve for A B and C

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anonymous
  • anonymous
Thank you, I think i have it now.
anonymous
  • anonymous
X(s)= 2/s - 2/7(s+1) +2/5(s+3)
anonymous
  • anonymous
I think it shoud be 7/2 and 5/2
anonymous
  • anonymous
X(s)= 2/s - 2/[7(s+1)] +2/[5(s+3)]*
anonymous
  • anonymous
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anonymous
  • anonymous
sorry for the late response the attached should be the answer. But I am sure you already got it =]
anonymous
  • anonymous
Thanx :)

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