anonymous
  • anonymous
LOKI!!!!!! HELPPPPPPP :P
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
LOL!
anonymous
  • anonymous
shut up lololol
anonymous
  • anonymous
alright =P ^=^

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More answers

anonymous
  • anonymous
he isint helping -/-
anonymous
  • anonymous
he's prolly drinking, eating , helping the gf or day dreaming lol
anonymous
  • anonymous
lmao
anonymous
  • anonymous
that's loki :) lol
anonymous
  • anonymous
I wish if there was a nudge button here to nudge the person you want to talk to :(
anonymous
  • anonymous
it would really help
anonymous
  • anonymous
i dont think anyone else here can do differential equations :(
anonymous
  • anonymous
lol, loki is here =D
anonymous
  • anonymous
Where's your initial condition?
anonymous
  • anonymous
LOKI
anonymous
  • anonymous
Hello
anonymous
  • anonymous
its 0,1
anonymous
  • anonymous
y(0)=1
anonymous
  • anonymous
okay, give me a few minutes to sort out something
anonymous
  • anonymous
What don't you get?
anonymous
  • anonymous
lemmy upload a pic
anonymous
  • anonymous
you actualy took REAL pics, wow
anonymous
  • anonymous
and my other option was... fake ones?
anonymous
  • anonymous
lol
anonymous
  • anonymous
well... it is just that you are the first person I see taking photos of your exercises and uploading them here, but no, you had no other options...
anonymous
  • anonymous
You don't think they just want you to solve the equation exactly for comparison? Family of solutions is all solutions with the constant intact.
anonymous
  • anonymous
Because for Euler's Method to work, you need a seed point.
anonymous
  • anonymous
i cant techniclly solve the equation, i do know other techniques of diff equation solving but i am supposed to, at the current point in time, know nothing more than eulers approximation and separation of variables
anonymous
  • anonymous
i believe the seen point in 0,1
anonymous
  • anonymous
then again i have no idea what a seed point is
anonymous
  • anonymous
yeah, you can use sep. vars. to solve this. You end up with \[x^2-y^2=c\]which is a family of hyperbola.
anonymous
  • anonymous
Seed point here is y(0)=1
anonymous
  • anonymous
hows you get x2-y2-c?????
anonymous
  • anonymous
If you look at that curve, you'll see that, when x=0, you have\[0-(y(0))^2=c \rightarrow y(0)=\pm \sqrt{-c}\]as a different seed.
anonymous
  • anonymous
The c would be less than or equal to zero (real solutions here).
anonymous
  • anonymous
where did that whole formula come from? O.o
anonymous
  • anonymous
\[\frac{dy}{dx}=\frac{x}{y}\rightarrow y dy = x dx \rightarrow \frac{y^2}{2}=\frac{x^2}{2}+c \rightarrow x^2-y^2=c\]
anonymous
  • anonymous
From this ^^
anonymous
  • anonymous
oh wow... separation of variables does work on this one... ive been confusing this with the last problem which was y'=x-y where seoaration doesnt work -.-
anonymous
  • anonymous
Basically, then, since the family of curves is defined by c, you can pick your y(0) to generate a new hyperbola within the family.
anonymous
  • anonymous
that was a big waste of time -.-
anonymous
  • anonymous
Your point would be (0,A) where A is 'Arman's choice'.
anonymous
  • anonymous
You panicked.
anonymous
  • anonymous
I myself have actually learned something ._. thank you loki
anonymous
  • anonymous
np sstarica :)
anonymous
  • anonymous
^_^ alright, off to bed soon, good night :)
anonymous
  • anonymous
night
anonymous
  • anonymous
isisnt it like midnight for u guys?
anonymous
  • anonymous
1:35 am
anonymous
  • anonymous
So you right with this one now?
anonymous
  • anonymous
k arman, i gotta go...my eyes are burning. see you round ;)
anonymous
  • anonymous
my bad for not replying, i was grpahing it ><

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