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anonymous

  • 5 years ago

LOKI!!!!!! HELPPPPPPP :P

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  1. anonymous
    • 5 years ago
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    LOL!

  2. anonymous
    • 5 years ago
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    shut up lololol

  3. anonymous
    • 5 years ago
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    alright =P ^=^

  4. anonymous
    • 5 years ago
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    he isint helping -/-

  5. anonymous
    • 5 years ago
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    he's prolly drinking, eating , helping the gf or day dreaming lol

  6. anonymous
    • 5 years ago
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    lmao

  7. anonymous
    • 5 years ago
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    that's loki :) lol

  8. anonymous
    • 5 years ago
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    I wish if there was a nudge button here to nudge the person you want to talk to :(

  9. anonymous
    • 5 years ago
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    it would really help

  10. anonymous
    • 5 years ago
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    i dont think anyone else here can do differential equations :(

  11. anonymous
    • 5 years ago
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    lol, loki is here =D

  12. anonymous
    • 5 years ago
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    Where's your initial condition?

  13. anonymous
    • 5 years ago
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    LOKI

  14. anonymous
    • 5 years ago
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    Hello

  15. anonymous
    • 5 years ago
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    its 0,1

  16. anonymous
    • 5 years ago
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    y(0)=1

  17. anonymous
    • 5 years ago
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    okay, give me a few minutes to sort out something

  18. anonymous
    • 5 years ago
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    What don't you get?

  19. anonymous
    • 5 years ago
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    lemmy upload a pic

  20. anonymous
    • 5 years ago
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  21. anonymous
    • 5 years ago
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    you actualy took REAL pics, wow

  22. anonymous
    • 5 years ago
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    and my other option was... fake ones?

  23. anonymous
    • 5 years ago
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    lol

  24. anonymous
    • 5 years ago
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    well... it is just that you are the first person I see taking photos of your exercises and uploading them here, but no, you had no other options...

  25. anonymous
    • 5 years ago
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    You don't think they just want you to solve the equation exactly for comparison? Family of solutions is all solutions with the constant intact.

  26. anonymous
    • 5 years ago
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    Because for Euler's Method to work, you need a seed point.

  27. anonymous
    • 5 years ago
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    i cant techniclly solve the equation, i do know other techniques of diff equation solving but i am supposed to, at the current point in time, know nothing more than eulers approximation and separation of variables

  28. anonymous
    • 5 years ago
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    i believe the seen point in 0,1

  29. anonymous
    • 5 years ago
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    then again i have no idea what a seed point is

  30. anonymous
    • 5 years ago
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    yeah, you can use sep. vars. to solve this. You end up with \[x^2-y^2=c\]which is a family of hyperbola.

  31. anonymous
    • 5 years ago
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    Seed point here is y(0)=1

  32. anonymous
    • 5 years ago
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    hows you get x2-y2-c?????

  33. anonymous
    • 5 years ago
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    If you look at that curve, you'll see that, when x=0, you have\[0-(y(0))^2=c \rightarrow y(0)=\pm \sqrt{-c}\]as a different seed.

  34. anonymous
    • 5 years ago
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    The c would be less than or equal to zero (real solutions here).

  35. anonymous
    • 5 years ago
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    where did that whole formula come from? O.o

  36. anonymous
    • 5 years ago
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    \[\frac{dy}{dx}=\frac{x}{y}\rightarrow y dy = x dx \rightarrow \frac{y^2}{2}=\frac{x^2}{2}+c \rightarrow x^2-y^2=c\]

  37. anonymous
    • 5 years ago
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    From this ^^

  38. anonymous
    • 5 years ago
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    oh wow... separation of variables does work on this one... ive been confusing this with the last problem which was y'=x-y where seoaration doesnt work -.-

  39. anonymous
    • 5 years ago
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    Basically, then, since the family of curves is defined by c, you can pick your y(0) to generate a new hyperbola within the family.

  40. anonymous
    • 5 years ago
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    that was a big waste of time -.-

  41. anonymous
    • 5 years ago
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    Your point would be (0,A) where A is 'Arman's choice'.

  42. anonymous
    • 5 years ago
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    You panicked.

  43. anonymous
    • 5 years ago
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    I myself have actually learned something ._. thank you loki

  44. anonymous
    • 5 years ago
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    np sstarica :)

  45. anonymous
    • 5 years ago
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    ^_^ alright, off to bed soon, good night :)

  46. anonymous
    • 5 years ago
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    night

  47. anonymous
    • 5 years ago
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    isisnt it like midnight for u guys?

  48. anonymous
    • 5 years ago
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    1:35 am

  49. anonymous
    • 5 years ago
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    So you right with this one now?

  50. anonymous
    • 5 years ago
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    k arman, i gotta go...my eyes are burning. see you round ;)

  51. anonymous
    • 5 years ago
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    my bad for not replying, i was grpahing it ><

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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