## anonymous 5 years ago derivative of (x^2+2)^2/3

1. anonymous

Hello, 123... You need to use the chain rule. If you let u=x^2+2, then$\frac{dy}{dx}=\frac{dy}{du}\frac{du}{dx}=\frac{d}{du}(\frac{u^2}{3}).\frac{d}{dx}(x^2+2)$$=\frac{2u}{3}.2x$$=\frac{2}{3}(x^2+1)(2x)=\frac{4x(x^2+1)}{3}$

2. anonymous

x^4+4 / 3