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anonymous

  • 5 years ago

how much pure acid must be added to 8mL of 20% acid solution in order to obtain a 50% acid solution?

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  1. anonymous
    • 5 years ago
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    So set it up the same way I did the last one. If you run into trouble, ask.

  2. amistre64
    • 5 years ago
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    8(.2) + y(1) = (8+y)(.5) solve for "y" :)

  3. anonymous
    • 5 years ago
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    thats what i came up with! thanks

  4. anonymous
    • 5 years ago
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    ok i tried to solve this and got 1.2 and thats not one of the mulitple choice options what am i doing wrong

  5. anonymous
    • 5 years ago
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    20(8) + 100(x) = 50(8+x) 100x + 160 = 400 + 50x 50x = 400 - 160 5x = 24 x = 4.8 ml

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