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  • 5 years ago

how do I rewrite the expression sin(pie/2 + x) in terms of sin x and cos x? thanks

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  1. anonymous
    • 5 years ago
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    Well at x = 0 the expression will have the value \(sin(\pi/2) = 1\). The value of the expression will always ahead of the typical sin function. At \(x = \pi\) the value of the expression will be -1. We can see that these values directly correspond to the values of the cosine function at 0, and pi respectively. \(sin(\pi/2 + x) = cos(x)\)

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