f(x)=X(squared)+8

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f(x)=X(squared)+8

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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and what do we need to do with this?
state the direction and the # of in which the graph of each function is translatedfrom the graph of f(x) = x squared
this is a graph...sorta of what you got
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x^2 normally rests on the x-axis, but this one is moved up by 8 units
since the 1st cooeficient is positive, it open up
would it be wide or narrow
If we let g(x) = \(x^2\) and f(x) = \(x^2+8\). We can see that f(x) will always be 8 units higher on the y axis than g(x) is. Thus f(x) is a translation of the graph of \(x^2\) up 8 units.
it is neither wider nor narrower than x^2, since there is no number other than a 1 infront of the x^2 part.
so it would stay same ok thanx
larger than one tends to make the slope steeper... and narrows the graph a fraction of a slope tends to flatten the slope and widen the graph
what if there is no y intercept like f(x) = 2x squared
the y intercept is there...its just zero :)
2x^2 +0
oh ok sorry im just startin alegebra 2 x.x a little rusty
y intercept just means tha the line of the graph gets intercepted, cuahgt by, crosses over, the y axis at a certain point. another name for the y axis is x=0. so whenever x=o you can find the y intercept
y = 2(0)^2...the y int = 0
y = (0)^2 + 8 the y int = 8
so if x=o there is no direction?
you have to define what you mean by "direction"
like on the first problem u found out the the graph is going 8 units
y = (x + "moves it side to side")^2 + "moves it up or down"
you understand that little "equation" I made?
i think so like if it were to be f(x)=2x sqaured the y will be a zero? so that will mean it has no direction?
correct as far as I am understaning your choice for "direction".. it simply means that the graph itself hasnt moved anywhere....but that "2" there means that the graph did get steeper...narrower
ok thank u :D
ok one more question how would u graph all of this usin y=mx+b or no
id go with no,.... y = mx +b makes a line...not a curve y = Mx^2 + b makes a curve since it has a "2" on the x. starts to bend the line

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