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and what do we need to do with this?

x^2 normally rests on the x-axis, but this one is moved up by 8 units

since the 1st cooeficient is positive, it open up

would it be wide or narrow

so it would stay same ok thanx

what if there is no y intercept like f(x) = 2x squared

the y intercept is there...its just zero :)

2x^2 +0

oh ok sorry im just startin alegebra 2 x.x a little rusty

y = 2(0)^2...the y int = 0

y = (0)^2 + 8
the y int = 8

so if x=o there is no direction?

you have to define what you mean by "direction"

like on the first problem u found out the the graph is going 8 units

y = (x + "moves it side to side")^2 + "moves it up or down"

you understand that little "equation" I made?

ok thank u :D

ok one more question how would u graph all of this usin y=mx+b or no