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anonymous

  • 5 years ago

lim x approaches 1 x-1/x^2+6x-7

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  1. amistre64
    • 5 years ago
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    is that x-1 on top of the rest? if so, try to use () to enclose the top and bottom parts...just makes it easier to read

  2. amistre64
    • 5 years ago
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    (x-1)/(x^2+6x-7) as x->1 we of course get an indeterminate number 0/0

  3. amistre64
    • 5 years ago
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    we should factor the bottom and see if that will elimiate some "problem" areas

  4. anonymous
    • 5 years ago
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    on top

  5. amistre64
    • 5 years ago
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    (x-1) --------- we see whats going on now (x+7)(x-1)

  6. anonymous
    • 5 years ago
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    Exactly got the same thing by factoring

  7. amistre64
    • 5 years ago
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    at x=1 there is a "hole" in the graph:

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  8. amistre64
    • 5 years ago
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    so the limit actually "approaches" 1/8 if we cancel terms and apply the limit

  9. anonymous
    • 5 years ago
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    Ah ok I follow.

  10. amistre64
    • 5 years ago
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    the graphs for 1/(x+7) and the one you wrote are the same except for one point....x=1 has a "hole" in yours, that isnt there in this one....

  11. anonymous
    • 5 years ago
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    Yeah I see that .

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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