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anonymous
 5 years ago
is dere any easy way i can do standard form to vertex form?
anonymous
 5 years ago
is dere any easy way i can do standard form to vertex form?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0probably; can you give an example?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(x)= ax^2+bx+c to f(x)=a(xh)^2+k

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0by completing the square

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yeah... you can find the "x" value for the vertex by taking the (middle#)/2(first#) that gives you your "h" value plug that in for equation to ge the "y" value for it....which will be the "k" does that make sense?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^2 12x + 45.... vertex = 12/2 = 6 = h (6)^2 12(6) +45 = k

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y = (x+6)^2 + ...the # you find for k

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(x)=4x^27x2 ?? can u show me this one?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i gave you a bad "equation"...lol...but the steps are good

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0h = 7/2(4) = 7/8 = 7/8

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0k = 4(7/8)^2 7(7/8) 2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0k = 460/64 reduce as needed if I did it right in me head ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0thats the "shortest" way I know...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im still kinda confuse but thanks :)
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