(n+6)(n+7) would the product of this be n^2+n+42??

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(n+6)(n+7) would the product of this be n^2+n+42??

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Nope. The product of the inner and outer terms don't add to be n.
ohh you add the inner terms instead of subtracting them
(a+b)(c+d) = (a+b)c + (a+b)d = ac + ad + bc + bd

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Other answers:

Use the FOIL method (First, Outer, Inner, Last). You multiply the two n's first (Your first terms), Then you multiply n & 7 (Your outer terms). Then you multiply n & 6 (Your inner terms) and then you multiply 6 & 7 (Your last terms)
You have to sum the products you get from the foil method. Sometimes it ends up being the sum of a negative number which leads to a middle term that's very small (or zero) but you're always adding these products together.

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