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anonymous
 5 years ago
∫x+1/2xx2+2 dx
anonymous
 5 years ago
∫x+1/2xx2+2 dx

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Pls guys help me solve this problem i have Exams tomorrow. pls

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know how to long divide polynomials?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's pretty much what you have to do here, so that your integral becomes (x+3)  (1/(x+1)). Then you can solve the integral.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hold up a minute, I think I messed it up, give me a minute or two.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the denominator is 2xx square + 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it looks like you separate by partial fractions \[x+1 =( Ax +B)/(2xx^2+2)\]. Because the deonimator is a irreducible quadratic eq. Once you solve for A and B, then you should have a differentiable eq.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry about the mix up before I jumped into a bad conclusion too fast.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits \left(2+\frac{1}{2 x}+xx^2\right) \, dx = 2 x+\frac{x^2}{2}\frac{x^3}{3}+\frac{\text{Log}[x]}{2} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that the final ans.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0from robtobey, Yes. Another version is the result factored: \[\frac{1}{6} \left(12 x+3 x^22 x^3+3 \text{Log}[x]\right) \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can check the result of the integration by taking the derivative of the result with respect to x.
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