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anonymous

  • 5 years ago

How would I write and expression for the following number sequence 4,6,10,18,34. I know that I am doubling number plus 2 that I had to each number.

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  1. amistre64
    • 5 years ago
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    write it out as an equation, right or wrong, give it your best shot... then we can have something to work with

  2. amistre64
    • 5 years ago
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    i see +2 +4 +8 +6 even number right?

  3. amistre64
    • 5 years ago
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    4+2 +4 4+6 +8 4+14 +16 4+30 see a pattern?

  4. anonymous
    • 5 years ago
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    four plus 2 = 6 than six plus 2 square yes

  5. anonymous
    • 5 years ago
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    n squared plus 2?

  6. amistre64
    • 5 years ago
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    4+2 +4 4+6 +8 4+14 +16 4+30 ----------------- +32 4+62 would be next right?

  7. amistre64
    • 5 years ago
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    2^n is the right most column

  8. anonymous
    • 5 years ago
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    yes

  9. amistre64
    • 5 years ago
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    2n + 2^n maybe?

  10. amistre64
    • 5 years ago
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    i was never good at these :)

  11. anonymous
    • 5 years ago
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    what do you mean? I have the pattern but the writing the expression is messing me up.

  12. amistre64
    • 5 years ago
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    the equation is just the pattern written out... really

  13. amistre64
    • 5 years ago
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    does n have to start at zero?

  14. amistre64
    • 5 years ago
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    " I know that I am doubling number plus 2 that I had to each number." is this your patter?

  15. amistre64
    • 5 years ago
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    2n is doubling a number... 2n + 2 is what I think you wrote....

  16. amistre64
    • 5 years ago
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    4,6,10,18,34 is this our only concern? its finite?

  17. anonymous
    • 5 years ago
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    ok try thus 2n square plus 2?

  18. amistre64
    • 5 years ago
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    2(1)^2 + 2 = 4 we missed "6" 2(2)^2 + 2 = 10

  19. amistre64
    • 5 years ago
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    2^n + ... 2^(1) + 2 = 4 2^(2) + 2 = 6 2^(3) + 2 = 10 2^(4) + 2 = 18 ....might be onto something here

  20. amistre64
    • 5 years ago
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    \[\sum_{1}^{4} (2^n +2)\]

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