anonymous
  • anonymous
How would I write and expression for the following number sequence 4,6,10,18,34. I know that I am doubling number plus 2 that I had to each number.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
write it out as an equation, right or wrong, give it your best shot... then we can have something to work with
amistre64
  • amistre64
i see +2 +4 +8 +6 even number right?
amistre64
  • amistre64
4+2 +4 4+6 +8 4+14 +16 4+30 see a pattern?

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More answers

anonymous
  • anonymous
four plus 2 = 6 than six plus 2 square yes
anonymous
  • anonymous
n squared plus 2?
amistre64
  • amistre64
4+2 +4 4+6 +8 4+14 +16 4+30 ----------------- +32 4+62 would be next right?
amistre64
  • amistre64
2^n is the right most column
anonymous
  • anonymous
yes
amistre64
  • amistre64
2n + 2^n maybe?
amistre64
  • amistre64
i was never good at these :)
anonymous
  • anonymous
what do you mean? I have the pattern but the writing the expression is messing me up.
amistre64
  • amistre64
the equation is just the pattern written out... really
amistre64
  • amistre64
does n have to start at zero?
amistre64
  • amistre64
" I know that I am doubling number plus 2 that I had to each number." is this your patter?
amistre64
  • amistre64
2n is doubling a number... 2n + 2 is what I think you wrote....
amistre64
  • amistre64
4,6,10,18,34 is this our only concern? its finite?
anonymous
  • anonymous
ok try thus 2n square plus 2?
amistre64
  • amistre64
2(1)^2 + 2 = 4 we missed "6" 2(2)^2 + 2 = 10
amistre64
  • amistre64
2^n + ... 2^(1) + 2 = 4 2^(2) + 2 = 6 2^(3) + 2 = 10 2^(4) + 2 = 18 ....might be onto something here
amistre64
  • amistre64
\[\sum_{1}^{4} (2^n +2)\]

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