ok im lost on trying this hw problem please explain how to do this (x-1)^2/5 = 4 im not sure how to factor the 2/5 power

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

ok im lost on trying this hw problem please explain how to do this (x-1)^2/5 = 4 im not sure how to factor the 2/5 power

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

use logs: log(x-1^2/5) = log(4) 2/5 log(x-1) = log(4) log(x-1) = 5/2 log(4) log(x-1) = log(4^5/2) x-1 = 4^(5/2) x = 1 + 4^(5/2)
or: 5root((x-1)^2) = 4 ^5 each side (x-1)^2 = 4^5 now square both sides x-1 = sqrt(4^5) x = 1+sqrt(4^5)
x = 1 + sqrt(4*4*4*4*4) x = 1+5sqrt(4) x = 1+5(2) x = 11 by chance?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

i missed something in that...im sure of it :)
this is suppose to be done by hand, i could easily throw it in the calculator and graph the equation for an answer. we have not learned anything about log yet awwwh that would work for me :) thx x is 32
x = 33 ...maybe
eeerr 33 i mean
my 5sqrt(4) up there is a result of my own stupidity....just ignore the person behind the curtain :)
lol thx yea i got it now i totally forgot how to do this
what is the 5root(32^2) anyway...
youre welcome :)
4

Not the answer you are looking for?

Search for more explanations.

Ask your own question