anonymous
  • anonymous
ok im lost on trying this hw problem please explain how to do this (x-1)^2/5 = 4 im not sure how to factor the 2/5 power
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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amistre64
  • amistre64
use logs: log(x-1^2/5) = log(4) 2/5 log(x-1) = log(4) log(x-1) = 5/2 log(4) log(x-1) = log(4^5/2) x-1 = 4^(5/2) x = 1 + 4^(5/2)
amistre64
  • amistre64
or: 5root((x-1)^2) = 4 ^5 each side (x-1)^2 = 4^5 now square both sides x-1 = sqrt(4^5) x = 1+sqrt(4^5)
amistre64
  • amistre64
x = 1 + sqrt(4*4*4*4*4) x = 1+5sqrt(4) x = 1+5(2) x = 11 by chance?

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amistre64
  • amistre64
i missed something in that...im sure of it :)
anonymous
  • anonymous
this is suppose to be done by hand, i could easily throw it in the calculator and graph the equation for an answer. we have not learned anything about log yet awwwh that would work for me :) thx x is 32
amistre64
  • amistre64
x = 33 ...maybe
anonymous
  • anonymous
eeerr 33 i mean
amistre64
  • amistre64
my 5sqrt(4) up there is a result of my own stupidity....just ignore the person behind the curtain :)
anonymous
  • anonymous
lol thx yea i got it now i totally forgot how to do this
amistre64
  • amistre64
what is the 5root(32^2) anyway...
amistre64
  • amistre64
youre welcome :)
anonymous
  • anonymous
4

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