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anonymous
 5 years ago
ok im lost on trying this hw problem please explain how to do this
(x1)^2/5 = 4 im not sure how to factor the 2/5 power
anonymous
 5 years ago
ok im lost on trying this hw problem please explain how to do this (x1)^2/5 = 4 im not sure how to factor the 2/5 power

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0use logs: log(x1^2/5) = log(4) 2/5 log(x1) = log(4) log(x1) = 5/2 log(4) log(x1) = log(4^5/2) x1 = 4^(5/2) x = 1 + 4^(5/2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0or: 5root((x1)^2) = 4 ^5 each side (x1)^2 = 4^5 now square both sides x1 = sqrt(4^5) x = 1+sqrt(4^5)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x = 1 + sqrt(4*4*4*4*4) x = 1+5sqrt(4) x = 1+5(2) x = 11 by chance?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i missed something in that...im sure of it :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is suppose to be done by hand, i could easily throw it in the calculator and graph the equation for an answer. we have not learned anything about log yet awwwh that would work for me :) thx x is 32

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0my 5sqrt(4) up there is a result of my own stupidity....just ignore the person behind the curtain :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol thx yea i got it now i totally forgot how to do this

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0what is the 5root(32^2) anyway...
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