## anonymous 5 years ago I am trying to determine if the following is absolutely or conditionally convergent or divergent....

1. anonymous

$\sum_{n=1}^{\infty} (\sin 4n / 4^{n})$

2. anonymous

Ok. We can treat sin(4n) as (-1)^n. This is because the sine function varies between -1 and 1.

3. anonymous

So that would give us [(-1)^n]/4^n. What kind of series does that look like?

4. anonymous

so use the alternating series test?

5. anonymous

Yes :)

6. anonymous

ok, for some reason I thought I could only do that with cos

7. anonymous

I don't know why

8. anonymous

Nope works for both. Don't worry I get hiccups like that all the time. :)

9. anonymous

thanks, pops!

10. anonymous

you just helped me too pops I am doing an assignment on that as we speak

11. anonymous