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anonymous

  • 5 years ago

How do you solve 4^x=20

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  1. anonymous
    • 5 years ago
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    Are you supposed to use a calculator for this problem or not?

  2. anonymous
    • 5 years ago
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    It would be hard to do without. I know I can't do logarithms in my head.

  3. anonymous
    • 5 years ago
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    Well it's possible that her instructor doesn't want an exact answer. That's why I'm curious.

  4. anonymous
    • 5 years ago
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    The calculator is allowed.

  5. anonymous
    • 5 years ago
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    Ok. Your going to convert to a logarithm. A log means that: the BASE of the log TO THE POWER of the ANSWER of the LOG will equal the number that's in ur log.

  6. anonymous
    • 5 years ago
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    But what your going to have to do is the change of base formula.

  7. anonymous
    • 5 years ago
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    Do you know how to do that?

  8. anonymous
    • 5 years ago
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    no

  9. anonymous
    • 5 years ago
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    ok. So what we're going to have after you convert to the form of the log is \[\log_{4} 20 = x\]

  10. anonymous
    • 5 years ago
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    To find the answer of this we need to use the change of base formula. The change of base formula says that you take the log of your argument (20) and divide it by the log of your base (4).

  11. anonymous
    • 5 years ago
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    When you do this, you should get the correct answer. But check to be sure if possible.

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