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anonymous
 5 years ago
A(t)=t^55t^4+20t^317 I am having trouble setting the derivative equal to zero. Please help!
anonymous
 5 years ago
A(t)=t^55t^4+20t^317 I am having trouble setting the derivative equal to zero. Please help!

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What did you get for the derivative?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I've got \[A' = 5t^420t^3 + 60t^2 = 5t^2(t^24t + 12)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0THat's exactly what I've got

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0a*b=0 implies either a=0 or b=0 or both=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well I know that 5t^2=0 but I when I solve the parentheses for 0 (using quadratic formula) it comes out negative. I can't fit that into the rest of my problem!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(I am solving for the intervals of increasing and decreasing in the function)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0you mean the number under the square root is negative?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so it is imaginary that means your only critical number is 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That just means that that part of the equation doesn't have any real roots.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay. So if I am solving for the intervals, do I just divide my number in half?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0I like using test points before and after each critical number

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You're looking for intervals for what? Where it's increasing and decreasing?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0the derivative tells us the slope therefore tells us if is increasing or decreasing so choose a number before and after 0 to see what if it is increasing or decreasing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So it's increasing from negative infinity to infinity, correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The derivative is always positive except at 0. So it is increasing for \(x \in (\infty,0) \bigcup (0,\infty)\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It is not increasing at 0.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0it has a horizontal tangent at x=0 thats what we found when we set A'=0

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0A'=0 means we are trying to find all x that has slope 0
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