anonymous
  • anonymous
in simplest form: 2x^2 + 5x - 7/x + 4 times x^2 + 4x/x^2 - 2x + 1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Hi Angelia
radar
  • radar
\[(2x ^{2}+5x-7)/(x+4)\times(x ^{2}+4x)/(x ^{2}-2x+1)\] Is this your equation?
anonymous
  • anonymous
2x^2 + 5x - 7 x^2 + 4x ------------- x ----------- x + 4 x^2 - 2x + 1 You have to factor each binomial/trinomial (2x + 7)(x - 1) x(x + 4) ------------- x --------- (x + 4) (x - 1)(x - 1) You then cancel the (x + 4)'s and the (x - 1)'s (only 1 of these on the bottom) x(2x + 7) ---------- x - 1

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radar
  • radar
I guess it was lol
anonymous
  • anonymous
Thanks blexting you really helped, I have one more problem
anonymous
  • anonymous
Sure.. go ahead
anonymous
  • anonymous
12x + 48/6x-15 times 4x^2-25/x^2 + 9x + 20
anonymous
  • anonymous
12x + 48 4x^2 - 25 ------------- x --------------- 6x - 15 x^2 + 9x + 20 12(x + 4) (2x + 5)(2x - 5) ---------- x --------------- 3(2x - 5) (x + 4)(x + 5) Cancel the (x + 4) and the (2x - 5) cancel the 3 up into the 12 leaving 4 4(2x + 5) --------- x + 5
anonymous
  • anonymous
When I was trying to do this problem on my own I messed up on the part 4x^2-25 I didn't have it factored correctly. You've been a big help to me. Thanks a lot!!!!!
anonymous
  • anonymous
Any time... Just remember that is the difference of two squares (2x)^2 and (5)^2 so you take what is in the ( )'s and add them and subtract them. (2x + 5)(2x - 5)
anonymous
  • anonymous
I don't have any homework tonight but I may have to have help tomorrow night if that's okay. Will you be on this site or the one you referred me to?
anonymous
  • anonymous
Email me and I will come on this site.
anonymous
  • anonymous
okay, I'll email you then. Hope you have a good night. Bye!!!
anonymous
  • anonymous
You too...

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