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  • 5 years ago

A pure sample of a compound that contains lithium and hydrogen weighs 0.537 g. If the sample is found to contain 0.469 g of lithium, what is the empirical formula of the compound?

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  1. anonymous
    • 5 years ago
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    i think you need atomic mass to do this. so you have .537g - .469 g = . 068g Hydrogen. atomic mass of Li is 6.94 g/mol and H is 1.01 g/mol. it's about .067 mols of Hydrogen and .067 mols of Lithium so the empirical formula is LiH. my chemistry is a little rusty but i think that is the solution.

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