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anonymous

  • 5 years ago

find a value of k so that the following equations are consistent: kx - 3y - 5 = 0 8x + y - 17 =0 kx + 2y -10 = 0 can k have more than one value satisfying this condition?

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  1. amistre64
    • 5 years ago
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    kx = 3y+5 kx = -2y +10

  2. amistre64
    • 5 years ago
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    0 = 5y -5 5 = 5y y = 1

  3. anonymous
    • 5 years ago
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    but what about the 2nd equation?

  4. amistre64
    • 5 years ago
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    kx = 8 k = 8/x when you find x :)

  5. amistre64
    • 5 years ago
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    8x +1 - 17 = 0 8x -16 = 0 8x = 16 x = 2

  6. amistre64
    • 5 years ago
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    k = 4

  7. anonymous
    • 5 years ago
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    can't you just add all three equations together and solve for x in terms of k? I got x = 25/(2k+8)

  8. amistre64
    • 5 years ago
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    add? no, you would need to use one of them as a "control" and subtract the other 2 from it if you were going that route

  9. amistre64
    • 5 years ago
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    x + y = 0 2x + 3y = 0 3x +4y = 0 ??? nah

  10. anonymous
    • 5 years ago
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    okay that's what I confused myself on. thanks.

  11. amistre64
    • 5 years ago
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    and since these are lines with different slopes, you cant have another value of "k" that would work.... thats just my gut feeling

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