## anonymous 5 years ago How do you find the derivative of xe^(lnx^2)?

1. anonymous

$xe^{\ln (2x^2)}$

2. myininaya

use the product rule then use chain rule

3. myininaya

first write y=x(2x^2)=2x^3 so all we really need now is the power rule if y is written this way

4. myininaya

y'=8x^2

5. amistre64

e^ln(x^2) = x^2 x(x^2) = x^3 y' = 3x^2 ... if I read it right :)

6. amistre64

myin is right for the other option ;)