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anonymous

  • 5 years ago

Find y', y = x / (x^2 - 1)^4

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  1. anonymous
    • 5 years ago
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    2x / 3(2x)^3, is that correct?

  2. anonymous
    • 5 years ago
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    Ops, 2x / 4(2x)^3

  3. anonymous
    • 5 years ago
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    Here's an easy way to solve problems like this. For a simple numerator or denominator you can bring the bottom to the top by making it exponent negative. So, you problem would become \[y=( x*(x ^{2}-1)^{-4})\] a product question instead of a quotient question. Use the product rule and you get \[(1/(x^{2}-1)^{4}) +( -8x^{2}/(x^{2}-1)^{5})\]

  4. anonymous
    • 5 years ago
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    Ahh! Thanks!

  5. anonymous
    • 5 years ago
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    Sorry. I tried and could not alone here. Could you give more details?

  6. anonymous
    • 5 years ago
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    Here's my work. Hope it helps. Pay close attention to the simplifying, that may be where you're having a problem, thats what got me when I was working on these.

  7. anonymous
    • 5 years ago
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    Sorry it came out sideways haha. Also don't forget you're chain rule, you're going to have to remember all of your rules for some of these, they can get pretty tricky.

  8. anonymous
    • 5 years ago
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    Thanks! now i got it!

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