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Is that the entirety of the question?
is a right prism just a cube?
not if it scales to 1:2....got it ;)
The solid described is similar to a large solid with the given scale factor. Find the surface area and volume of a larger solid
the shape of the solid doesnt matter? or does it. a right prism can be anything as long as it is the same shape stacked up on top of itself.... or am I mistaken?
the easies thing to do is to make it a rectangular prism...i think
82/6 would be a square prism with 6 equal sides ...
but that doesnt work out evenly
Volume = l*w*h = 42 As = Area of faces
im at a loss....sorry...
maybe; 4 side + 2 bases = 82 that would still be a rectanule prism,,,,
if it had square bases then 4wh + 2w = 82 would be simpler
4wh + 2w^2 = 82 42 = w^2h h = 42/w^2 4(42/w) + 2w^2 = 82
168/w + 2w^2 = 82 168 + 2w^3 = 82w 2w^3 -82w +168 = 0 2(w^3 - 41w + 84) = 0 w^3 - 41w + 84 = 0 is what I got so far if I did it right
this just seems harder than what it should be called for :)
and it looks like my w is going negative....... which doesnt bode well for my plans.....
if we knew the original shape for the base of this right prism, id be better to calculate..... other than that....sorry